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the velocity of a particle is given by v=at^2+bt+c,where v is in m/s, time t is in second abd a b,c are the cons†an ts. the unit of the quantity abc is
Velocity of a particle=At + Bt². A and B are constants. Find the distance between 1 and 2 seconds : Without using integration.
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For two matrices A and B, A = begin{bmatrix} 2& 1 & 3 4 & 1 & 0end{bmatrix}, B = begin{bmatrix} 1& -1 0 & 2 5 & 0end{bmatrix}, verify that (AB)^{T} = B^{T} A^{T}.
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Solved] . 1 5 A = B = 1 -3 u = 3 19 - 1 7. Calculate: (a) A + BT, (b) AB,... | Course Hero
![SOLVED: -1 Let A = [11 23] B= [ -1 8o= -3 and D = [s] Consider the following expressions: 1. AB 2. AC BT C 4.A+ D 5. B+cT 6. CD](https://cdn.numerade.com/ask_images/eed6c72a38ab4e94b7b591462960467d.jpg "SOLVED: -1 Let A = [11 23] B= [ -1 8o= -3 and D = [s] Consider the following expressions: 1. AB 2. AC BT C 4.A+ D 5. B+cT 6. CD")
SOLVED: -1 Let A = [11 23] B= [ -1 8o= -3 and D = [s] Consider the following expressions: 1. AB 2. AC BT C 4.A+ D 5. B+cT 6. CD
![For the matrices A and B, verify that (AB)T=BTAT, where A=[1324],B=[1425].](https://search-static.byjusweb.com/question-images/toppr_ext/questions/1393632_1660985_ans_fc5fae7f52ff4e42b10a8265f73dd1af.jpg "For the matrices A and B, verify that (AB)T=BTAT, where A=[1324],B=[1425].")